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15 June, 09:09

The square root 41 is between two consecutive integers

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Answers (2)
  1. 15 June, 09:24
    0
    √41≈6.4

    So the two integers would be 6 and 7

    *note that this is a poor question as the square root of 41 is ±√41≈±6.4, and integers can be positive or negative so technically the root is between - 7 and - 6 as well.
  2. 15 June, 09:36
    0
    6 and 7 (root of 41 is about 6.403)
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