The product of two consecutive even integers is 10 less than 5 times their sum. find the two integers

Let a=2k and b = (2k+2) such that ab=5 (a+b) - 10

That is, 2k (2k+2) = (10k+10k+10) - 10.

Thus, 4k^2+4k=20k.

4k^2-16k=0

4k (k-4) = 0

k=0,4

That implies 4*6=5 (4+6) - 10 or

0*2=5 (0+2) - 10

I believe 0 and 2 are the only values which work.

The integers are 3 and 5