Ask Question
8 August, 12:36

11. 10ac * 6ab * (-2bc) = ?

A. 14a2b2c2

B. 2a + 2b + 2c + 14

C. - 120a2b2c2

D. 2a + 2b + 2c - 120

+4
Answers (1)
  1. 8 August, 12:48
    0
    C. - 120a2b2c2

    Step-by-step explanation:

    We'll just the multiplications one at a time ...

    10ac * 6ab * (-2bc) = 60a²bc * (-2bc) (multiplying 10ac * 6ab)

    60a²bc * (-2bc) = - 120a²b²c²

    We just have to multiply the numbers together (like 10 and 6),

    then all similar letters together (like ac * ab = a²bc). If a letter is already present (like a in this example), then we add up its powers a * a = a², a² * a would be a³ and so on). If the letter is not present (like 'b' in 'ac', we suppose it's there as b^0 which is equal to 1) ... so we still add up its exponent (power) ... so it makes b^0 * b = b
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “11. 10ac * 6ab * (-2bc) = ? A. 14a2b2c2 B. 2a + 2b + 2c + 14 C. - 120a2b2c2 D. 2a + 2b + 2c - 120 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers