The length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and width

Length = l = 3x

Width = w = 2x

P = 2l + 2w

P = 2 (3x) + 2 (2x)

530 = 6x + 4x

530 = 10x

53 = x

Length = 3x = 3 (53) = 318 / 2 sides = 159

Width = 2x = 2 (53) = 212 / 2 sides = 106

the length of the lot is 159 yards

the width of the lot is 106 yards