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23 November, 06:29

How do i solve for x (ax+bx) / 3=c in terms of a and b and c

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  1. 23 November, 06:43
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    Already in terms of c x (ax+bx) / 3=c

    (ax^2 + bx^2) / 3=c. Multiply parentheses by x

    ax^2 + bx^2=3c. Multiply each side by 3

    ax+bx=√3c. Take the square root of both sides

    x (a+b) = √3c

    a+b=√3c/x

    a=√3c/x - b or b=√3c/x - a
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