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Neil Wilkins
Mathematics
18 September, 14:27
2log6+6log2/4log2+log27-log9=2
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Ollie
18 September, 14:49
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(2log6 + 6log2) / (4log2 + log27 - log9) = (log6^2 + log2^6) / (log2^4 + log27 - log9) = (log36 + log 64) / (log 16 + log (27/9)) = log (36 x 64) / (log 16 + log 3) = log 2304 / log (16 x 3) = log 48^2 / log 48 = 2log48 / log 48 = 2.
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