The following equation f (x) = x³ + 0.5x² + 4.5 has only 1 real root. It lies between the interval [-1,0].

We are asked in this problem to find the real root of the polynomial f (x) = x3 + 0.5x2 + 4.5. in this case, to find the root of the equation, we equate the equation to zero.

f (x) = x³ + 0.5x² + 4.5 = 0

2x3 + x^2 + 9 = 0

x1=-1.83557

x2=0.66779+1.41619∗i

x3=0.66779-1.41619∗i

answer is - 1.84