Two hot air balloons are traveling along the same path away from a town, beginning from different locations at the same time. Henry's balloon begins 15 miles from the town and is 31 miles from each the town after two hours. The distance of Tasha's balloon from the town is represented by the function y=5x + 25

Question

Maxwell Gilbert

Mathematics

1 February, 13:21

Two hot air balloons are traveling along the same path away from a town, beginning from different locations at the same time. Henry's balloon begins 15 miles from the town and is 31 miles from each the town after two hours. The distance of Tasha's balloon from the town is represented by the function y=5x + 25

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Claudia · Answer 1

Henry's balloon was farther from the town at the beginning and Henry's balloon traveled more quickly.

Step-by-step explanation:

The distance of Tasha's balloon from the town is represented by the function y = 8x + 20 ... (1)

Where y is the distance in miles from the town and x represents the time of fly in hours.

So, at the start of the journey i. e. at x = 0, y = 20 miles {From equation (1) } from the town.

Again, Tasha's balloon is traveling at a rate of 8 miles per hour.

Now, Henry's balloon begins 30 miles from the town and is 48 miles from the town after 2 hours.

So, Henry's balloon traveling with the speed of miles per hour.

Therefore, Henry's balloon was farther from the town at the beginning i. e. 30 miles from the town. And Henry's balloon traveled more quickly i. e at the rate of 9 miles per hour.