Write an equation for a linear function whose graph has the given characteristics.

Passes through (42,0), perpendicular to the graph of g (x) = 6x+2

f (x) =

G (x) = 6x + 2 ... the slope here is 6. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal slope, we flip the original slope and change the sign. So our perpendicular line will have a slope of - 1/6. (see how I flipped 6 (or 6/1) and made it 1/6, then I changed the sign and made it - 1/6)

y = mx + b

slope (m) = - 1/6

(42,0) ... x = 42 and y = 0

now we sub and find b, the y int

0 = - 1/6 (42) + b

0 = - 7 + b

7 = b

so ur perpendicular equation is : y = - 1/6x + 7 ... or f (x) = - 1/6x + 7