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25 August, 21:49

3n^2-2n-8 Factoring trinomials II

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  1. 25 August, 22:08
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    (3n + 4) (n-2)

    Step-by-step explanation:

    Are you asking to factor this 3n^2 - 2n - 8?

    If so the best way to do this problem is with the X method.

    top: 3 * (-8)

    left: factor of 3*-8 right: factor of 3*-8

    bottom: - 2

    try the factors 4 and - 6 because 4*-6 = 3 * -8 = - 24

    Because notice that 4 + - 6 = - 2

    so:

    3n^2 - 2n - 8 can be rewritten as 3n^2 - 6n + 4n - 8

    We should first use Distributive property to factor: 3n^2 - 6n + 4n - 8

    3n^2 - 6n + 4n - 8 = 3n (n - 2) + 4 (n - 2)

    Now we factor by grouping here : (3n + 4) (n-2)

    I factored out the group (n-2)

    Therefore: (3n + 4) (n-2) = 3n^2 - 2n - 8
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