Find three consecutive even integers. Such as that 5 times of the first integer is 18 more than the sum of second and third interferes

The numbers would be 2, 4, and 6.

Step-by-step explanation:

In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.

5 (x) = x + 2 + x + 4

5x = 2x + 6

3x = 6

x = 2

Since the first number is 2, we know the next two are 4 and 6.