A drive in theater charges $3.50 per car, the drive in already admitted 100 cars, solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$

They need to admit 43 more cars to make at least $500

Solution:

Given, A drive in theater charges $3.50 per car,

The drive in already admitted 100 cars,

Then, money collected until now is $ 3.50 x 100 = $ 350

We have to solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$

Now, let the number of cars need to be admitted be "n"

Then, inequality is:

collected amount + needed amount ≥ $ 500

$ 350 + $ 3.50 x n ≥ $ 500

350 + 3.5n ≥ 500

3.5n ≥ 500 - 350

On solving, we get

3.5n ≥ 150

n ≥ 42.857

As number of cars can't be fractions, n = 43

Hence, they need to admit 43 more cars to make at least $500