Bob is a high school basketball player. he is a 70% free throw shooter. that means his probability of making a free throw is 0.70. during the season, what is the probability that bob makes his third free throw on his fifth shot? what is e (x) ?

Since Bob makes 70% of free throws, P (probability of success) = 0.70. x (number of trials) is five because there are a total of five shots. R (number of successes) = 3 because we are determining whether or not the third free throw will be successful. We will use the following formula b * (x; r, P) = x-1Cr-1 * Pr * Qx - r b * (5; 3, 0.7) = 4C2 * 0.73 * 0.32 b * (5; 3, 0.7) = 6 * 0.343 * 0.09 = 0.18522 The probability he will make the shot is 0.18522. For the purpose of this problem, X=0.70