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23 April, 20:46

A plumber charges an initial fee of $200 plus and hourly fee of $50. Mrs. Coombs paid the plumber $ 450. How many hours did the plumber work?

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Answers (2)
  1. 23 April, 20:48
    0
    5 hours

    Step-by-step explanation:

    The total cost is the fee plus the hours * hourly cost

    450 = 200+50*h where h is the hours

    Subtract 200 from each side

    450-200 = 200-200 + 50h

    250 = 50h

    Divide each side by 50

    250/50 = 50h/50

    5 = h

    5 hours
  2. 23 April, 20:53
    0
    5

    Step-by-step explanation:

    Ok, so the question is asking us how many hours the plumber worked, which makes it a variable, so let's call it x, times an hourly rate of $50. We already know she paid 200 so let's make that into an equation.

    450 = 50x + 200

    We need to isolate x, so we have to subtract 200 from each side. The equation should know look like this:

    250 = 50x

    Now in order to determine x, we need to divide by 50 on both sides.

    X = 5

    So the plumber worked a total of 5 hours.
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