The length of a rectangle is 1m more than twice its width, and the area of the rectangle is 66m2. Find the dimensions of the rectangle.

A = LW

A = 66

L = 2W + 1

66 = W (2W + 1)

66 = 2W^2 + W

2W^2 + W - 66 = 0

(2W - 11) (W + 6) = 0

2W - 11 = 0

2W = 11

W = 11/2

W = 5.5

W + 6 = 0

W = - 6 (this is an extraneous solution ... it will not work)

L = 2W + 1 = 2 (5.5) + 1 = 12

so ur dimensions are : Length = 12m and width = 5.5m