Find 3 consecutive positive integers such that the product of the first and third integers is 48. Solve algebraically.

Question

Conor Atkinson

Mathematics

14 November, 04:00

Find 3 consecutive positive integers such that the product of the first and third integers is 48. Solve algebraically.

+3

Answers (1)

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Tessa Case · Answer 1

Let integers be x, x+1 and x+2

x (x + 2) = 48

x^2 + 2x - 48 = 0

(x + 8) (x - 6) = 0

x = 6 (because the integrs are positive

so the 3 numbers are 6,7 and 8.