Ask Question
18 August, 11:16

Solve: 3 (2d-1) - 2d=4 (d-2) + 5

A. d=0

B. d=4

C. No Solution

D. Infinitely many solutions

+4
Answers (1)
  1. 18 August, 11:46
    0
    3 (2D-1) - 2D = 4 (D-2) + 5

    6D-3-2D = 4D-8+5

    4D-3 = 4D-8+5

    4D-3 = 4D-3

    4D = 4D-6

    0 = - 6

    The answer is C, no solution
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Solve: 3 (2d-1) - 2d=4 (d-2) + 5 A. d=0 B. d=4 C. No Solution D. Infinitely many solutions ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers