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25 May, 00:51

Working together, 4 computers can complete a task in 11 minutes. if 2 of the original computes are replace with computers that each run 20% faster, how many minutes will it

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  1. 25 May, 01:03
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    First, let's make an equation out of the first sentence in the problem statement. When four of each computers are used, they can finish a task in 11 minutes together. The question is, how fast is the rate of each computer? We let that rate be x which is in units of hours per unit computer. So, the first equation would be:

    4x = 11

    Solving for x,

    x = 2.75 minutes

    That means that each of the four computers has an individual rate of 2.75 minutes. Now, for the succeeding sentence, we replace two of the computers with a much faster time. That means it would take a shorter time by 20%. The new time would then be:

    New time = 2.75 (1 - 0.2) = 2.2 minutes

    Therefore, the total amount of time for the task to be done by 2 original and 2 new computers is

    Total time = 2 (2.75) + 2 (2.2)

    Total time = 9.9 minutes
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