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23 August, 10:50

The temperature of a chemical solution is originally 21^/circ/text{C}21 ∘ C. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^/circ/text{C}75 ∘ C after 1212 minutes of heating. The temperature, TT, of the solution in ^/circ/text{C} ∘ C is a function of xx, the heating time in minutes. Write the function's formula.

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  1. 23 August, 10:57
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    Answer: The required function is,

    T (x) = 21 + 4.5 x

    Step-by-step explanation:

    The original temperature of the solution = 21° C

    Let the temperature is increasing with a constant rate of y degree per minutes,

    Thus, the temperature of the solution after 12 minutes = 21 + 12 y

    According to the question,

    21° + 12 y = 75°

    ⇒ 12 y = 54°

    ⇒ y = 4.5°

    Hence, the constant rate of increasing the temperature = 4.5° per minutes,

    Thus, the temperature of the solution after x minutes,

    T (x) = 21 + 4.5 x

    Which is the required function.
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