find K if the sum of the zeros of the polynomial x square - (K + 6) x + 2 (2 k - 1) is half the product

k=7

given a quadratic polynomial

ax^2+bx+c

the sum of the roots is given by - (b/a)

and the product of the roots as (c/a)

hence we get sum of roots as - ( - (k+6) / 1) and product of roots as (2 (2k-1)) / 1

since the sum is equal to half the Product then we get

k+6=2k-1 and solving for k we get 7