There were about 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were between 700 - 799 pounds. How many of the 340,000 cattle placed on feed were between 700-799 pounds?

Weight Group. Fraction of total cattle

less than 600. 1/5

pounds.

600-699. 11/50

700-799. 2/5

800. 9/20

Question

Alexander Cohen

Mathematics

Today, 02:21

There were about 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were between 700 - 799 pounds. How many of the 340,000 cattle placed on feed were between 700-799 pounds?

Weight Group. Fraction of total cattle

less than 600. 1/5

pounds.

600-699. 11/50

700-799. 2/5

800. 9/20

+4

Answers (2)

Know the Answer?

Cheyanne · Answer 1

So, a certain number out of 340,000 will gives us the ratio of how many cows are 700-799 or 2/5, meaning the x out of 340,000 is equivalent to 2/5.

x/340,000 = 2/5

5x = 170,000

5x/5 = 170,000/5

x = 340,000

Elizabeth Price · Answer 2

Maybe this could clarify it:

2/5=1/5+1/5

therefore:

(340,000) * 2/5=340,000/5 + 340,000/5

So two fifths of all the cattle is equivilant to 68,000 times two, aka 136,000