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31 May, 14:30

Over which interval is the graph of f (x) = - x^+3x+8 increasing?

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  1. 31 May, 14:41
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    It is increasing in the interval (-∞, 3/2).

    Step-by-step explanation:

    y = - x^2 + 3x + 8

    The derivative is:

    dy/dx = - 2x + 3

    This is the slope of tangent to the curve so when f (x) is increasing

    -2x + 3 > 0

    -2x > - 3

    x < 3/2

    So it is increasing in the interval (-∞, 3/2)
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