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29 January, 04:51

Solve the equation x^13-2x^12-x^11+2x^10=0 in the real number system

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  1. 29 January, 05:14
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    x = {0; - 1; 2; 1}

    Step-by-step explanation:

    x¹³-2x¹²-x¹¹+2x¹⁰=0

    x¹⁰ (x³-2x²-x+2) = 0

    x¹⁰ (x+1) (x-2) (x-1) = 0

    x¹⁰=0 ∨ x+1=0 ∨ x-2=0 ∨ x-1=0

    x=0 x = - 1 x = 2 x = 1
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