A line passes throughout (-3,-2) and is perpendicular to 3x-2y=7. What is the equation of the line in slope-intercept form? A. Y=3/2X B. Y=3/2x+4 C. y=-2/3x-4 D. y=/2/3x

3x - 2y = 7

-2y = - 3x + 7

y = 3/2x - 7/2 ... slope of this line is 3/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is - 2/3 (see how I flipped the slope and changed the sign)

y = mx + b

slope (m) = - 2/3

(-3,-2) ... x = - 3 and y = - 2

now we sub and find b, the y int

-2 = - 2/3 (-3) = b

-2 = 2 + b

-2 - 2 = b

-4 = b

so ur perpendicular equation is : y = - 2/3x - 4 <==