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21 January, 21:18

The path of a model rocket can be represented by the equation h (t) = - t2+15t+16, where h (t) is the height, in feet, of the rocket at any given time, t. what is the height of the model rocket after 3 seconds from launch?

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  1. 21 January, 21:36
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    The height is 52 feet.

    Using t=3, we have:

    -3² + 15 (3) + 16 = - 9 + 45 + 16 = 52
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