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21 January, 00:58

1.) Peggy walks at a rate of 2 miles per hour and jogs at a rate of 4 miles per hour. She walked and jogged 3.4 miles in 1.2 hours. For how long did Peggy jog and for how long did she walked?

2.) A pilot flew his plane 2400 miles in 8 hours flying with the wind. Flying against the wind over the same route, he returned in 10 hours. What was the rate of the plane and of the wind?

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Answers (2)
  1. 21 January, 01:06
    0
    She spent 42 minutes walking and 30 minutes jogging
  2. 21 January, 01:20
    0
    1.

    time she spent walking = T

    time she spent jogging = 1.2 - T

    2T + 4 (1.2 - T) = 3.4

    2T + 4.8 - 4T = 3.4

    2T - 4T = 3.4 - 4.8

    - 2T = - 1.4

    T = - 1.4-2 = 0.7 hours = 42 minutes

    Time she spent jogging = 1.2-0.7 = 0.5 hours = 30 minutes

    2.

    Against wind : 2400 miles in 10 hours

    With wind : 2400 miles in 8 hours

    Speed of plane = x

    Speed of wind = y

    t=d/r

    against the wind speed x-y mph

    with the wind x=y mph

    2400 / (x-y) = 10

    2400 = 10x-10y

    240 = x-y eq. 1

    2400/x+y=8

    2400 = 8x+8y

    300 = x+y eq 2

    Add eq1 & eq 2 = 740 = 2x

    X = 740/2 = 370 mph for plane

    300 = 370 + y

    Y = 370-300 = 70 mph wind speed
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