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8 June, 03:02

Using the quadratic formula to solve x^2=5-x what are the values of x?

a. - 1 + / - √21/2

b.-1 + / - √19i/2

c. 5 + / - √21/2

d. 1 + / - √19i/2

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Answers (1)
  1. 8 June, 03:27
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    A

    you have to solve x^2+x-5=0

    So x = (-1 + / - sqrt (1^2+4*1*5)) / 2

    x = (-1 + / - sqrt (21)) / 2
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