Ask Question
5 June, 00:24

Find the center of the circle whose equation is (x-2) ^2 (y-4) ^2=9.

A. (-2,-4)

B. (2,4)

C. (4,2)

+1
Answers (1)
  1. 5 June, 00:45
    0
    B. (2,4)

    Step-by-step explanation:

    The equation for a circle is written as

    (x-h) ^2 + (y-k) ^2 = r^2

    where (h, k) is the center and r is the radius

    (x-2) ^2 + (y-4) ^2=9.

    Rewriting this equation

    (x-2) ^2 + (y-4) ^2=3^2

    The center is at (2,4)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the center of the circle whose equation is (x-2) ^2 (y-4) ^2=9. A. (-2,-4) B. (2,4) C. (4,2) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers