Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation 2x2 + 4x + 8 = 0.

Which explanation could Anderson provide?

The equation has no real number solutions because the discriminant is 0.

The equation has one real number solution because the discriminant is 0.

O The equation has no real number solutions because the discriminant is less than 0.

The equation has two real number solutions because the discriminant is greater than 0.

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Question

Trey Keith

Mathematics

11 September, 16:13

Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation 2x2 + 4x + 8 = 0.

Which explanation could Anderson provide?

The equation has no real number solutions because the discriminant is 0.

The equation has one real number solution because the discriminant is 0.

O The equation has no real number solutions because the discriminant is less than 0.

The equation has two real number solutions because the discriminant is greater than 0.

Mark this and return

and Exit

Next

Submit

+2

Answers (1)

Know the Answer?

Kathleen Cowan · Answer 1

No real number solutions.

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 (a ≠ 0)

The discriminant is b² - 4ac

• If b² - 4ac > 0 the equation has 2 real and distinct roots

• If b² - 4ac = 0 the equation has 2 real and equal roots

• If b² - 4ac < 0 the equation has no real roots

Given

2x² + 4x + 8 = 0 ← in standard form

with a = 2, b = 4 and c = 8, then

b² - 4ac = 4² - (4 * 2 * 8) = 16 - 64 = - 48, thus

The equation has no real number solutions because the discriminant is < 0