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11 September, 16:13

Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation 2x2 + 4x + 8 = 0.

Which explanation could Anderson provide?

The equation has no real number solutions because the discriminant is 0.

The equation has one real number solution because the discriminant is 0.

O The equation has no real number solutions because the discriminant is less than 0.

The equation has two real number solutions because the discriminant is greater than 0.

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  1. 11 September, 16:22
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    No real number solutions.

    Step-by-step explanation:

    Given a quadratic equation in standard form

    ax² + bx + c = 0 (a ≠ 0)

    The discriminant is b² - 4ac

    • If b² - 4ac > 0 the equation has 2 real and distinct roots

    • If b² - 4ac = 0 the equation has 2 real and equal roots

    • If b² - 4ac < 0 the equation has no real roots

    Given

    2x² + 4x + 8 = 0 ← in standard form

    with a = 2, b = 4 and c = 8, then

    b² - 4ac = 4² - (4 * 2 * 8) = 16 - 64 = - 48, thus

    The equation has no real number solutions because the discriminant is < 0
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