Calculate a6 for the geometric sequence in which a1=1500 and the common ratio is 3/5.

The sum would be a₅ = 506.25!

Step-by-step explanation:

Given that,

first term a₁ = 1600

common ratio (r) =

We need to find the fifth term of the geometric progression

We know that the nth term formula

aₙ = a₁rⁿ-¹

where a₁ is first term and r is the common ratio

n is the number of terms

So, n = 5

a₅ = 1600

a₅ = 1600*

a₅ = 1600*81/256

a₅ =

a₅ = 506.25