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6 January, 23:49

If f (0) = 287 and 5+4i is a root, what is the standard form of the polynomial function?

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  1. 7 January, 00:06
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    If a+bi is a root, then a-bi is also a root

    5+4i is a root, 5-4i is also a root

    if f (0) = 287

    For f (0) = 287, therefor it is

    f (x) = sometingx+287 since the x's cancel for f (0)

    5-4i and 5+4i

    (x - (5-4i)) and (x - (5+4i))

    (x-5+4i) (x-5-4i)

    x^2-10x+41

    right now, f (x) = 41

    41*what=287

    Divide both sides by 41

    what=7

    time whole equation by that

    f (x) = 7 (x^2-10x+41)

    f (x) = 7x^2-70x+287
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