Jose rented a truck for one day. There was a base fee of $14.99, and there was an additional charge of 83 cents for each mile driven. Jose had to pay $238.26 when he returned the truck. For how many miles did he drive the truck?

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Ali

Mathematics

23 August, 23:01

Jose rented a truck for one day. There was a base fee of $14.99, and there was an additional charge of 83 cents for each mile driven. Jose had to pay $238.26 when he returned the truck. For how many miles did he drive the truck?

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Juliana Trujillo · Answer 1

Hi! So, the base fee was $14.99, which is the price you only pay one time. $0.83 was charged per mile driven, so the price changes constantly per mile driven. He had to pay $238.26 total when he returned the truck. To make this problem easier to solve, let's make an equation in this form: 14.99 + 0.83m = 238.26. In these kinds of formulas, suntract 14.99 from both sides to make the "m" by itself. When you do that, you get 0.83m = 223.27. Now to find the answer, divide each side by 0.83 to isolate the "m". 223.27/0.83 is 269. Let's plug it in to see if it works. 269 * 0.83 is 223.27. 223.27 + 14.99 is 238.26. There. Jose drove 269 miles with the truck. m = 269.