Ask Question
27 June, 18:18

1) Tickets to a fundraiser are $14 if purchased ahead of time and $25 if

purchased at the door. The total amount raised from all ticket sales was $625. If

eleven tickets were purchased at the door, how many tickets were purchased

chead of time?

+5
Answers (2)
  1. 27 June, 18:23
    0
    25 tickets were purchased ahead of time

    Step-by-step explanation:

    25 (11) = 275 which is the price of the 11 bought at the door then you take 625-275=350 which is the amount of money that was raised through purchases ahead of time so you take 350/14=25 meaning that 25 tickets were bought ahead of time.
  2. 27 June, 18:41
    0
    25

    Step-by-step explanation:

    625 = 11 (d) + x (a)

    625 = (11x25) + 14a

    625 = 275 + 14a

    350 = 14a

    a = 350/14

    a = 25

    Therefore, 25 tickets were purchased ahead of time.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “1) Tickets to a fundraiser are $14 if purchased ahead of time and $25 if purchased at the door. The total amount raised from all ticket ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers