1) Tickets to a fundraiser are $14 if purchased ahead of time and $25 if

purchased at the door. The total amount raised from all ticket sales was $625. If

eleven tickets were purchased at the door, how many tickets were purchased

chead of time?

Question

Yair Dillon

Mathematics

27 June, 18:18

1) Tickets to a fundraiser are $14 if purchased ahead of time and $25 if

purchased at the door. The total amount raised from all ticket sales was $625. If

eleven tickets were purchased at the door, how many tickets were purchased

chead of time?

+5

Answers (2)

Know the Answer?

Keyon Coleman · Answer 1

25 tickets were purchased ahead of time

Step-by-step explanation:

25 (11) = 275 which is the price of the 11 bought at the door then you take 625-275=350 which is the amount of money that was raised through purchases ahead of time so you take 350/14=25 meaning that 25 tickets were bought ahead of time.

Eleanor · Answer 2

25

Step-by-step explanation:

625 = 11 (d) + x (a)

625 = (11x25) + 14a

625 = 275 + 14a

350 = 14a

a = 350/14

a = 25

Therefore, 25 tickets were purchased ahead of time.

1) Tickets to a fundraiser are $14 if purchased ahead of time and $25 ifpurchased at the door. The total amount raised from all ticket sales was $625. Ifeleven tickets were purchased at the door, how many tickets were purchasedchead of time?

1) Tickets to a fundraiser are $14 if purchased ahead of time and $25 if

purchased at the door. The total amount raised from all ticket sales was $625. If

eleven tickets were purchased at the door, how many tickets were purchased

chead of time?