Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers

4 consecutive odd integers ... x, x + 2, x + 4, x + 6

product of 2 smaller numbers is 64 less then the product of the 2 larger numbers ...

x (x + 2) = (x + 4) (x + 6) - 64

x^2 + 2x = (x^2 + 10x + 24 - 64)

x^2 + 2x = x^2 + 10x - 40

2x = 10x - 40

2x - 10x = - 40

-8x = - 40

x = - 40/-8

x = 5

x + 2 = 5 + 2 = 7

x + 4 = 5 + 4 = 9

x + 6 = 5 + 6 = 11

ur numbers are : 5,7,9, and 11

The answers are 5,7,9 and 11