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13 August, 17:38

Write an equation in slope intercept form for a line that is parallel and perpendicular to the line y=5x-3 and has a y intercept of 6

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  1. 13 August, 17:39
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    Parallel lines have the same slope so the line parallel to y = 5x - 3 with a y-intercept of 6 would be y = 5x + 6

    For perpendicular, the slope is negative reciprocal of the original line. So negative reciprocal of 5 would be - 1/5

    Therefore the perpendicular line would be y = - 1/5x + 6
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