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3 December, 03:20

Consider the given function.

f (x) = x^2 - 14x - 72

What are the zeros and axis of symmetry for the graph of the function?

A.

zeros: x = - 9 and x = - 8;

axis of symmetry: x = - 7

B.

zeros: x = - 18 and x = 4;

axis of symmetry: x = - 7

C.

zeros: x = 9 and x = 8;

axis of symmetry: x = 7

D.

zeros: x = - 4 and x = 18;

axis of symmetry: x = 7

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Answers (1)
  1. 3 December, 03:21
    0
    D)

    Step-by-step explanation:

    f (x) = x^2 - 14x - 72

    0=x^2 - 14x-72

    0=x^2 - 18x+4x-72

    0=x (x-18) + 4 (x-18)

    0 = (x-18) (x+4)

    x-18=0 or x+4=0

    x1=18 or x2=-4

    asis of symmetry: x = (x1+x2) / 2

    x = (18 + (-4)) / 2

    x=14/2

    x=7
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