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12 May, 12:37

Find the cube roots of 27 (cos 327° + i sin 327°). Write the answer in trigonometric form.

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  1. 12 May, 13:07
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    3 (cos 109° + i sin 109°)

    3 (cos 229° + i sin 229°)

    3 (cos 349° + i sin 349°)

    Step-by-step explanation:

    27 (cos 327° + i sin 327°)

    Modulus: 27^⅓ = 3

    Arguments:

    327/3 = 109

    (327+360) / 3 = 229

    (327+2 (360)) / 3 = 347

    Cube roots are:

    3 (cos 109° + i sin 109°)

    3 (cos 229° + i sin 229°)

    3 (cos 349° + i sin 349°)
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