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Van Goodman
Mathematics
5 February, 01:37
What is the slope of f (x) = x^2+3 when x=-1?
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Armani Mayo
5 February, 02:05
0
F (x) = (-1) ^2+3
f (x) = 1+3
f (x) = 4
The slope is 0 because 4 is a constant.
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