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11 June, 11:12

Fifteen of the 100 digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select a DVR that is not defective? The probability is nothing.

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Answers (2)
  1. 11 June, 11:18
    0
    17/20

    Step-by-step explanation:

    Fifteen of the 100 digital video recorders (DVRs) in an inventory are known to be defective, the total number of non-defective DVRs will be 100-15 = 85 DVRs.

    If 85 DVRs are not defective, the probability that you randomly select a DVR that is not defective can be expressed as:

    P (non-defective DVRs) = Total number of non-defective DVRs / Total DVRs

    P (non-defective DVRs) = 85/100

    P (non-defective DVRs) = 17/20
  2. 11 June, 11:22
    0
    0.85

    Step-by-step explanation:

    Given;

    Number of defective DVRs D = 15

    Total number of DVRs T = 100

    Number of non defective DVR N = T - D = 100 - 15 = 85

    The probability of selecting a non defective DVR P (N) is equal to the number of non defective DVR divided by the total number of DVRs.

    P (N) = N/T

    Substituting the values;

    P (N) = 85/100

    P (N) = 17/20 = 0.85
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