A region is bounded in the second quadrant by the curve y=ln (1-x), the line y=3, and the y-axis. Find the area of the region.

Would the interval be 3 and 0 and would the equation be set up like 3-ln (1-x) upper bound 3 and lower bound 0?

Question

13 March, 02:55

+5

Answers (1)

Know the Answer?

Madelynn Bates · Answer 1

Yes that's right, the intervals would be 3 and 0, and 3-ln (1-x) upper bound 3 and lower bound 0. Exactly.

A region is bounded in the second quadrant by the curve y=ln (1-x), the line y=3, and the y-axis. Find the area of the region.Would the interval be 3 and 0 and would the equation be set up like 3-ln (1-x) upper bound 3 and lower bound 0?