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9 August, 02:40

How many solutions exist for the system of equations given below?

3a + 4b = 20

12a = 80 - 16b

A. One Solution

B. Two Solutions

C. Infinitely many solutions

D. No solutions

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Answers (2)
  1. 9 August, 02:44
    0
    3a+4b = 20

    rewrite the second equation by adding 16b to each side

    12a+16b = 80

    divide each side by 4

    3a+4b = 20

    they are the same equation,

    there are infinitely many solutions
  2. 9 August, 03:08
    0
    3a + 4b = 20

    4b = 20 - 3a

    b = 5 - 3/4 a

    12a = 80 - 16 (5 - 3/4 a)

    12a = 80 - 80 + 12a

    12a = 12a

    C. Infinitely many solutions
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