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28 June, 02:52

Andrew invested $3,100 in an account paying an interest rate of 2.1% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 16 years?

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  1. 28 June, 03:15
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    Answer: $4338 would be in the account after 16 years.

    Step-by-step explanation:

    The formula for continuously compounded interest is

    A = P x e (r x t)

    Where

    A represents the future value of the investment after t years.

    P represents the present value or initial amount invested

    r represents the interest rate

    t represents the time in years for which the investment was made.

    e is the mathematical constant approximated as 2.7183.

    From the information given,

    P = $3100

    r = 2.1% = 2.1/100 = 0.021

    t = 16 years

    Therefore,

    A = 3100 x 2.7183^ (0.021 x 16)

    A = 3100 x 2.7183^ (0.336)

    A = $4338 to the nearest dollar
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