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23 September, 14:35

A rectangles length is 7 inches greater than its width. If the perimeter of the rectangle is 110 inches, find its length and width.

I think it's w (w+7) = 110

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Answers (2)
  1. 23 September, 14:51
    0
    Ythat's wrong, perimiter is 2l+2w or 2 (l+w) or just look below at my explanation

    l=w+7

    perimiter=2l+2w

    perimiter=2 (l+w)

    subsitute

    2 (w+7+w) = permiter

    2w+14+2w=4w+14=permiter

    4w+14=110

    subtract 14 from both sides

    4w=96

    divide both sides by 4

    w=24

    width=24

    l=w+7

    l=24+7

    l=31

    legnth=31

    width=24
  2. 23 September, 14:54
    0
    The equation for perimeter is P=2 (l+w)

    so, the equation is 110=2 (l+w)

    we know that l is 7 inches greater than w

    so, l=w+7

    now, substitute that for l

    110=2 (w+7+w)

    110=2 (2w+7)

    110=4w+14

    96=4w

    w=24
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