During a recent eruption, a piece of ash was ejected from a volcano with an initial velocity of 368 ft/sec.
The height (H), in feet, of our ash projectile is given by the equation
H=16t^2 + 368t
Where t is time, in seconds.
The graph of the equation will be a parabola
Assume the volcano does not have a height. So, H = 0 and t=0
1.) when does the ash projectile reach it's maximum height?
2.) What is the maximum height?
3.) When does the ash projectile return to the ground?
+4
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “During a recent eruption, a piece of ash was ejected from a volcano with an initial velocity of 368 ft/sec. The height (H), in feet, of our ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Home » Mathematics » During a recent eruption, a piece of ash was ejected from a volcano with an initial velocity of 368 ft/sec. The height (H), in feet, of our ash projectile is given by the equation H=16t^2 + 368t Where t is time, in seconds.