Amirah Arnold

Mathematics

8 May, 05:05

During a recent eruption, a piece of ash was ejected from a volcano with an initial velocity of 368 ft/sec.

The height (H), in feet, of our ash projectile is given by the equation

H=16t^2 + 368t

Where t is time, in seconds.

The graph of the equation will be a parabola

Assume the volcano does not have a height. So, H = 0 and t=0

1.) when does the ash projectile reach it's maximum height?

2.) What is the maximum height?

3.) When does the ash projectile return to the ground?