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6 February, 17:34

Two cyclist leave towns 78 miles apart at the same time and travel toward each other. One cyclist travels 5 mi/h faster than the other. If they meet in 2 hours, what is the rate of each cyclist?

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  1. 6 February, 17:37
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    One cyclist travels at 17 m/h and the other at 22 m/h.

    Step-by-step explanation:

    Let one cyclist travel at x m/h and the other at (x+5) m/h.

    Their combined speed is x + x + 5 = 2x+5 m/h.

    When they meet the total distance they have travelled will be 78 miles.

    Speed = distance / time taken, so:

    2x+5 = 78/2

    2x + 5 = 39

    2x = 34

    x = 17 m/h = speed of one cyclist.

    So the other travels at 17+5 = 22 m/h.
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