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Vaughn Wallace
Mathematics
22 March, 11:55
Given cscx = - 5/2 between 270 and 360 find sin2x
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Lillianna Ferguson
22 March, 12:17
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Hello:
cscx = - 5/2
1/sinx = - 5/2
sinx=-2/5
sin²x+cos²x=1
4/25+cos²x=25/25
cos²x = 21/25
between 270 and 360 : cosx > 0 cosx = (√21) / 5
but : sin2x = 2sinx cosx
sin2x = 2 (-2/5) ((√21) / 5)
sin2x = (-4√21) / 25
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