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22 March, 11:55

Given cscx = - 5/2 between 270 and 360 find sin2x

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  1. 22 March, 12:17
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    Hello:

    cscx = - 5/2

    1/sinx = - 5/2

    sinx=-2/5

    sin²x+cos²x=1

    4/25+cos²x=25/25

    cos²x = 21/25

    between 270 and 360 : cosx > 0 cosx = (√21) / 5

    but : sin2x = 2sinx cosx

    sin2x = 2 (-2/5) ((√21) / 5)

    sin2x = (-4√21) / 25
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