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3 March, 21:27

A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?

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Answers (1)
  1. 3 March, 21:33
    0
    To find the 'maximum height' we will need to take the derivative of h (t) = - 16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
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