A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?

Question

Karly Glenn

Mathematics

3 March, 21:27

A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?

+1

Answers (1)

Know the Answer?

Demarcus Shields · Answer 1

To find the 'maximum height' we will need to take the derivative of h (t) = - 16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.

A ball is thrown into the air with an upwardvelocity of 32 ft/s. Its height h in feet after t secondsis given by the function h = - 16t2 + 32t + 6. In howmany seconds does the ball reach its maximumheight? Round to the nearest hundredth if necessary.What is the ball's maximum height?

A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?