What 3 consecutive even integers are 3 times the sum of the first two was 58 less than 14 times the opposite of the third?

Even integers are 2 apart

they are

x, x+2, x+4

so

smallest is x, biggest is x+4

3 (x+x+2) = - 58+14 (-1) (x+4)

simplify

3 (2x+2) = - 58-14 (x+4)

expand

6x+6=-58-14x-56

6x+6=-14x-114

add 14x both sides

20x+6=-114

minus 6 both sides

20x=-120

divide both sides by 20

x=-6

x+2=-4

x+4=-2

de numbers are - 6,-4,-2