Find the integral of arccos x / sqrt (1-x^2) dx.

The problem ask to find the integral of the trigonometric equation of arcos x/qrt (1-x^2) dx and the best answer that i could give base on the given equation and my further computation and that is ∫arccos (x) / sqrt (1 - x2 dx) = 1/2 (arccos (x)) 2 + c. I hope are satisfied with my answer and feel free to ask for more