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Mathematics
1 September, 13:21
1 + sec2x sin2x = sec2x
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Braden Bailey
1 September, 13:43
0
1+sec²x sin²x=
1 + (1/cos²x) sin²x=
1+sin²x / cos²x=
(cos²x + sin²x) / cos²x=
1/cos²x=
sec²x
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